Why you should use Innebygd C Online test?

The Innebygd C -test makes use of scenario-based questions to test for on-the-job skills as opposed to theoretical knowledge, ensuring that candidates who do well on this screening test have the relavant skills. The questions are designed to covered following on-the-job aspects: Ekspertise innen C -grunnleggende inkludert variabler, datatyper, erklæringer og funksjoner Sterk forståelse av innebygde C -grunnleggende inkludert registre, direktiver og drivere Kompetanse i å jobbe med pekere, inkludert matriser, strukturer og fagforeninger Dybdekunnskap om bitoperasjoner, inkludert emballasjedata, utpakking av data og bitmanipulasjoner Erfaring med I/O -operasjoner i C og dens korrelasjoner i innebygde systemer Kjennskap til objektorienterte prinsipper som polymorfisme, arv og innkapsling Forståelse av internt av samler og kompilator Evne til effektivt feilsøkingskode og håndtere feil Kunnskap om kompilatoroptimaliseringsteknikker Erfaring med tverrbaserte verktøykjeder

Innebygd C Online test

About the test:

Den innebygde C-testen bruker scenaribaserte MCQ-spørsmål for å evaluere en kandidats evne til å utvikle C/ innebygde C-drivere/ biblioteker og kodingsspørsmål for å evaluere praktiske C-programmeringsferdigheter. Kode-sporing av MCQ-spørsmål evaluerer innebygde C-grunnleggende (datatyper, variabler, pekere), I/O-maskinvareadresse, fastpunkts aritmetiske operasjoner, tilgang til adresseområder, forbehandler direktiver og effektiv anvendelse av objektorienterte programmeringsprinsipper for firmwareutvikling.

Covered skills:

C Grunnleggende (variabler; datatyper; erklæringer; funksjoner)
Pekere (med matriser; strukturer; fagforeninger)
I/O i C og korrelasjoner i innebygde systemer
Internals av Assembler og kompilator
Kompilatoroptimalisering
Headerbeskyttelse

Innebygde C -grunnleggende (registre; direktiver; drivere)
Bitoperasjoner (emballasjedata; utpakking av data; bit manipulasjoner)
Objektorienterte prinsipper (polymorfisme; arv; innkapsling)
Feilsøking og feilhåndtering
Tverrkomponering av verktøykjeder
Oppstartssekvens

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9 reasons why

Adaface Innebygd C Test is the most accurate way to shortlist Embedded Software Engineers

Reason #1

Tests for on-the-job skills

The Innebygd C Online test helps recruiters and hiring managers identify qualified candidates from a pool of resumes, and helps in taking objective hiring decisions. It reduces the administrative overhead of interviewing too many candidates and saves time by filtering out unqualified candidates at the first step of the hiring process.

The test screens for the following skills that hiring managers look for in candidates:

Evne til å skrive godt strukturert og effektiv C-kode
Kjennskap til innebygde systemer og bruk av registre, direktiver og drivere
Kompetanse i å jobbe med pekere i forskjellige scenarier, inkludert matriser, strukturer og fagforeninger
Evne til å utføre bitoperasjoner som emballasje og pakke ut data, samt bitmanipulasjoner
Forståelse av I/O i C og dens korrelasjon med innebygde systemer
Kunnskap om objektorienterte prinsipper som polymorfisme, arv og innkapsling
Bevissthet om internt om samlere og kompilatorer
Kompetanse i feilsøking og feilhåndtering
Evne til å optimalisere kode ved hjelp av en kompilator
Erfaring med tverrbaserte verktøykjeder
Forståelse av headerbeskyttelse
Kunnskap om oppstartssekvensen i innebygde systemer

Reason #2

No trick questions

Traditional assessment tools use trick questions and puzzles for the screening, which creates a lot of frustration among candidates about having to go through irrelevant screening assessments.

View sample questions

The main reason we started Adaface is that traditional pre-employment assessment platforms are not a fair way for companies to evaluate candidates. At Adaface, our mission is to help companies find great candidates by assessing on-the-job skills required for a role.

Why we started Adaface

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Reason #3

Non-googleable questions

We have a very high focus on the quality of questions that test for on-the-job skills. Every question is non-googleable and we have a very high bar for the level of subject matter experts we onboard to create these questions. We have crawlers to check if any of the questions are leaked online. If/ when a question gets leaked, we get an alert. We change the question for you & let you know.

How we design questions

Dette er bare en liten prøve fra biblioteket vårt med 10.000+ spørsmål. De faktiske spørsmålene om dette Innebygd C -test vil være ikke-googlable.

🧐 Question
Easy Logic Black Box	Solve
Consider the following logic box. There are three inputs A, B, C and three outputs not A, not B and not C (not A = !A, not B = !B, not C = !C). Is it possible to achieve the expected outputs from the inputs using: - Only AND and OR gates - Just two (2) NOT gates - No NAND, NOR, XOR, or XNOR gates
Medium Memory Map Memory Architecture	Solve
Review the following Embedded Systems code and memory map of 16-bit microcontroller: Here are the specifications of the microcontroller: - The stack grows from area D, whereas the program and static variables are stored in area C - ‘int’ in the system is a 16-bit number - There is no operating system and no memory protection - The program is compiled and loaded into area C Pick the correct statements: A: first_var, second_var and input will be in area D B: first_var and second_var will be in area C, input will be in area D C: If the contents of 0x0010 at the start of the program is 7, the program will print 0 and exit D: If the contents of 0x0010 at the start of the program is 42, the program will print 0 and exit E: If the contents of 0x0010 at the start of the program is 42, the program will overflow the stack overwriting the program and static variables region F: If the program overflows and overwrites the program and static variables region, arbitrary data is executed as if it is the program, causing unpredictable results
Medium Multi-tasking Multi-tasking	Solve
Review the following Embedded Systems code: Here’s the specification for the program: - first_var and second_var are global variables shared among several threads - first_lock and second_lock are mutex locks that protect access to first_var and second_var - Reads and writes to variables first_var and second_var are not guaranteed to be atomic - No locks must be acquired unnecessarily - Acquire second_var lock first before acquiring first_var lock by any thread that is going to use both first_var and second_var Assume that if a thread attempts to acquire a lock it already holds, then it is immediately granted the lock. Pick the correct statements: A: The provided code does not meet the specification completely since second_lock is not acquired before acquiring first_lock for procedure 'foo' B: Replacing foo with logic of foo1 makes sure locks are not acquired unnecessarily and second_lock is acquired before acquiring first_lock C: Replacing foo with logic of foo1 makes sure second_lock is acquired before acquiring first_lock but there are cases when second_lock is acquired unnecessarily (when first_var < input) D: Replacing foo with logic of foo2 makes sure locks are not acquired unnecessarily E: Replacing foo with logic of foo2 is optimized version of foo1 but there are cases when second_lock is still acquired unnecessarily (when first_var value changes from the time ‘res’ value is computed and by the first_lock is acquired again.
Medium Memory Allocation	Solve
Check the following three C functions: Which among these will likely cause issues with pointers?
Medium Pointers and Structs	Solve
What is the output of the following C code?
Medium Strings Strings	Solve
What is the output of the following C code?
Easy Registration Queue Logic Queues	Solve
We want to register students for the next semester. All students have a receipt which shows the amount pending for the previous semester. A positive amount (or zero) represents that the student has paid extra fees, and a negative amount represents that they have pending fees to be paid. The students are in a queue for the registration. We want to arrange the students in a way such that the students who have a positive amount on the receipt get registered first as compared to the students who have a negative amount. We are given a queue in the form of an array containing the pending amount. For example, if the initial queue is [20, 70, -40, 30, -10], then the final queue will be [20, 70, 30, -40, -10]. Note that the sequence of students should not be changed while arranging them unless required to meet the condition. ⚠️⚠️⚠️ Note: - The first line of the input is the length of the array. The second line contains all the elements of the array. - The input is already parsed into an array of "strings" and passed to a function. You will need to convert string to integer/number type inside the function. - You need to "print" the final result (not return it) to pass the test cases. For the example discussed above, the input will be: 5 20 70 -40 30 -10 Your code needs to print the following to the standard output: 20 70 30 -40 -10
Medium Visitors Count Strings Logic	Solve
A manager hires a staff member to keep a record of the number of men, women, and children visiting the museum daily. The staff will note W if any women visit, M for men, and C for children. You need to write code that takes the string that represents the visits and prints the count of men, woman and children. The sequencing should be in decreasing order. Example: Input: WWMMWWCCC Expected Output: 4W3C2M Explanation: ‘W’ has the highest count, then ‘C’, then ‘M’. ⚠️⚠️⚠️ Note: - The input is already parsed and passed to a function. - You need to "print" the final result (not return it) to pass the test cases. - If the input is- “MMW”, then the expected output is "2M1W" since there is no ‘C’. - If any of them have the same count, the output should follow this order - M, W, C.

	🧐 Question	🔧 Skill
	Easy Logic Black Box	3 mins Embedded Systems	Solve
Consider the following logic box. There are three inputs A, B, C and three outputs not A, not B and not C (not A = !A, not B = !B, not C = !C). Is it possible to achieve the expected outputs from the inputs using: - Only AND and OR gates - Just two (2) NOT gates - No NAND, NOR, XOR, or XNOR gates
	Medium Memory Map Memory Architecture	3 mins Embedded Systems	Solve
Review the following Embedded Systems code and memory map of 16-bit microcontroller: Here are the specifications of the microcontroller: - The stack grows from area D, whereas the program and static variables are stored in area C - ‘int’ in the system is a 16-bit number - There is no operating system and no memory protection - The program is compiled and loaded into area C Pick the correct statements: A: first_var, second_var and input will be in area D B: first_var and second_var will be in area C, input will be in area D C: If the contents of 0x0010 at the start of the program is 7, the program will print 0 and exit D: If the contents of 0x0010 at the start of the program is 42, the program will print 0 and exit E: If the contents of 0x0010 at the start of the program is 42, the program will overflow the stack overwriting the program and static variables region F: If the program overflows and overwrites the program and static variables region, arbitrary data is executed as if it is the program, causing unpredictable results
	Medium Multi-tasking Multi-tasking	2 mins Embedded Systems	Solve
Review the following Embedded Systems code: Here’s the specification for the program: - first_var and second_var are global variables shared among several threads - first_lock and second_lock are mutex locks that protect access to first_var and second_var - Reads and writes to variables first_var and second_var are not guaranteed to be atomic - No locks must be acquired unnecessarily - Acquire second_var lock first before acquiring first_var lock by any thread that is going to use both first_var and second_var Assume that if a thread attempts to acquire a lock it already holds, then it is immediately granted the lock. Pick the correct statements: A: The provided code does not meet the specification completely since second_lock is not acquired before acquiring first_lock for procedure 'foo' B: Replacing foo with logic of foo1 makes sure locks are not acquired unnecessarily and second_lock is acquired before acquiring first_lock C: Replacing foo with logic of foo1 makes sure second_lock is acquired before acquiring first_lock but there are cases when second_lock is acquired unnecessarily (when first_var < input) D: Replacing foo with logic of foo2 makes sure locks are not acquired unnecessarily E: Replacing foo with logic of foo2 is optimized version of foo1 but there are cases when second_lock is still acquired unnecessarily (when first_var value changes from the time ‘res’ value is computed and by the first_lock is acquired again.
	Medium Memory Allocation	2 mins C	Solve
Check the following three C functions: Which among these will likely cause issues with pointers?
	Medium Pointers and Structs	2 mins C	Solve
What is the output of the following C code?
	Medium Strings Strings	2 mins C	Solve
What is the output of the following C code?
	Easy Registration Queue Logic Queues	30 mins Coding	Solve
We want to register students for the next semester. All students have a receipt which shows the amount pending for the previous semester. A positive amount (or zero) represents that the student has paid extra fees, and a negative amount represents that they have pending fees to be paid. The students are in a queue for the registration. We want to arrange the students in a way such that the students who have a positive amount on the receipt get registered first as compared to the students who have a negative amount. We are given a queue in the form of an array containing the pending amount. For example, if the initial queue is [20, 70, -40, 30, -10], then the final queue will be [20, 70, 30, -40, -10]. Note that the sequence of students should not be changed while arranging them unless required to meet the condition. ⚠️⚠️⚠️ Note: - The first line of the input is the length of the array. The second line contains all the elements of the array. - The input is already parsed into an array of "strings" and passed to a function. You will need to convert string to integer/number type inside the function. - You need to "print" the final result (not return it) to pass the test cases. For the example discussed above, the input will be: 5 20 70 -40 30 -10 Your code needs to print the following to the standard output: 20 70 30 -40 -10
	Medium Visitors Count Strings Logic	30 mins Coding	Solve
A manager hires a staff member to keep a record of the number of men, women, and children visiting the museum daily. The staff will note W if any women visit, M for men, and C for children. You need to write code that takes the string that represents the visits and prints the count of men, woman and children. The sequencing should be in decreasing order. Example: Input: WWMMWWCCC Expected Output: 4W3C2M Explanation: ‘W’ has the highest count, then ‘C’, then ‘M’. ⚠️⚠️⚠️ Note: - The input is already parsed and passed to a function. - You need to "print" the final result (not return it) to pass the test cases. - If the input is- “MMW”, then the expected output is "2M1W" since there is no ‘C’. - If any of them have the same count, the output should follow this order - M, W, C.

	🧐 Question	🔧 Skill	💪 Difficulty	⌛ Time
	Logic Black Box	Embedded Systems	Easy	3 mins	Solve
Consider the following logic box. There are three inputs A, B, C and three outputs not A, not B and not C (not A = !A, not B = !B, not C = !C). Is it possible to achieve the expected outputs from the inputs using: - Only AND and OR gates - Just two (2) NOT gates - No NAND, NOR, XOR, or XNOR gates
	Memory Map Memory Architecture	Embedded Systems	Medium	3 mins	Solve
Review the following Embedded Systems code and memory map of 16-bit microcontroller: Here are the specifications of the microcontroller: - The stack grows from area D, whereas the program and static variables are stored in area C - ‘int’ in the system is a 16-bit number - There is no operating system and no memory protection - The program is compiled and loaded into area C Pick the correct statements: A: first_var, second_var and input will be in area D B: first_var and second_var will be in area C, input will be in area D C: If the contents of 0x0010 at the start of the program is 7, the program will print 0 and exit D: If the contents of 0x0010 at the start of the program is 42, the program will print 0 and exit E: If the contents of 0x0010 at the start of the program is 42, the program will overflow the stack overwriting the program and static variables region F: If the program overflows and overwrites the program and static variables region, arbitrary data is executed as if it is the program, causing unpredictable results
	Multi-tasking Multi-tasking	Embedded Systems	Medium	2 mins	Solve
Review the following Embedded Systems code: Here’s the specification for the program: - first_var and second_var are global variables shared among several threads - first_lock and second_lock are mutex locks that protect access to first_var and second_var - Reads and writes to variables first_var and second_var are not guaranteed to be atomic - No locks must be acquired unnecessarily - Acquire second_var lock first before acquiring first_var lock by any thread that is going to use both first_var and second_var Assume that if a thread attempts to acquire a lock it already holds, then it is immediately granted the lock. Pick the correct statements: A: The provided code does not meet the specification completely since second_lock is not acquired before acquiring first_lock for procedure 'foo' B: Replacing foo with logic of foo1 makes sure locks are not acquired unnecessarily and second_lock is acquired before acquiring first_lock C: Replacing foo with logic of foo1 makes sure second_lock is acquired before acquiring first_lock but there are cases when second_lock is acquired unnecessarily (when first_var < input) D: Replacing foo with logic of foo2 makes sure locks are not acquired unnecessarily E: Replacing foo with logic of foo2 is optimized version of foo1 but there are cases when second_lock is still acquired unnecessarily (when first_var value changes from the time ‘res’ value is computed and by the first_lock is acquired again.
	Memory Allocation	C	Medium	2 mins	Solve
Check the following three C functions: Which among these will likely cause issues with pointers?
	Pointers and Structs	C	Medium	2 mins	Solve
What is the output of the following C code?
	Strings Strings	C	Medium	2 mins	Solve
What is the output of the following C code?
	Registration Queue Logic Queues	Coding	Easy	30 mins	Solve
We want to register students for the next semester. All students have a receipt which shows the amount pending for the previous semester. A positive amount (or zero) represents that the student has paid extra fees, and a negative amount represents that they have pending fees to be paid. The students are in a queue for the registration. We want to arrange the students in a way such that the students who have a positive amount on the receipt get registered first as compared to the students who have a negative amount. We are given a queue in the form of an array containing the pending amount. For example, if the initial queue is [20, 70, -40, 30, -10], then the final queue will be [20, 70, 30, -40, -10]. Note that the sequence of students should not be changed while arranging them unless required to meet the condition. ⚠️⚠️⚠️ Note: - The first line of the input is the length of the array. The second line contains all the elements of the array. - The input is already parsed into an array of "strings" and passed to a function. You will need to convert string to integer/number type inside the function. - You need to "print" the final result (not return it) to pass the test cases. For the example discussed above, the input will be: 5 20 70 -40 30 -10 Your code needs to print the following to the standard output: 20 70 30 -40 -10
	Visitors Count Strings Logic	Coding	Medium	30 mins	Solve
A manager hires a staff member to keep a record of the number of men, women, and children visiting the museum daily. The staff will note W if any women visit, M for men, and C for children. You need to write code that takes the string that represents the visits and prints the count of men, woman and children. The sequencing should be in decreasing order. Example: Input: WWMMWWCCC Expected Output: 4W3C2M Explanation: ‘W’ has the highest count, then ‘C’, then ‘M’. ⚠️⚠️⚠️ Note: - The input is already parsed and passed to a function. - You need to "print" the final result (not return it) to pass the test cases. - If the input is- “MMW”, then the expected output is "2M1W" since there is no ‘C’. - If any of them have the same count, the output should follow this order - M, W, C.

Reason #4

1200+ customers in 75 countries

Med Adaface var vi i stand til å optimalisere den første screeningsprosessen vår med oppover 75 %, og frigjorde dyrebar tid for både ansettelsesledere og vårt talentanskaffelsesteam!

Brandon Lee, Leder for mennesker, Love, Bonito

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Reason #5

Designed for elimination, not selection

The most important thing while implementing the pre-employment Innebygd C -test in your hiring process is that it is an elimination tool, not a selection tool. In other words: you want to use the test to eliminate the candidates who do poorly on the test, not to select the candidates who come out at the top. While they are super valuable, pre-employment tests do not paint the entire picture of a candidate’s abilities, knowledge, and motivations. Multiple easy questions are more predictive of a candidate's ability than fewer hard questions. Harder questions are often "trick" based questions, which do not provide any meaningful signal about the candidate's skillset.

Science behind Adaface tests

Reason #6

1 click candidate invites

Email invites: You can send candidates an email invite to the Innebygd C -test from your dashboard by entering their email address.

Public link: You can create a public link for each test that you can share with candidates.

API or integrations: You can invite candidates directly from your ATS by using our pre-built integrations with popular ATS systems or building a custom integration with your in-house ATS.

Reason #7

Detailed scorecards & benchmarks

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Reason #8

High completion rate

Adaface tests are conversational, low-stress, and take just 25-40 mins to complete.

This is why Adaface has the highest test-completion rate (86%), which is more than 2x better than traditional assessments.

Reason #9

Advanced Proctoring

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About the Innebygd C Assessment Test

Why you should use Pre-employment Innebygd C Online test?

The Innebygd C -test makes use of scenario-based questions to test for on-the-job skills as opposed to theoretical knowledge, ensuring that candidates who do well on this screening test have the relavant skills. The questions are designed to covered following on-the-job aspects:

Ekspertise innen C -grunnleggende inkludert variabler, datatyper, erklæringer og funksjoner
Sterk forståelse av innebygde C -grunnleggende inkludert registre, direktiver og drivere
Kompetanse i å jobbe med pekere, inkludert matriser, strukturer og fagforeninger
Dybdekunnskap om bitoperasjoner, inkludert emballasjedata, utpakking av data og bitmanipulasjoner
Erfaring med I/O -operasjoner i C og dens korrelasjoner i innebygde systemer
Kjennskap til objektorienterte prinsipper som polymorfisme, arv og innkapsling
Forståelse av internt av samler og kompilator
Evne til effektivt feilsøkingskode og håndtere feil
Kunnskap om kompilatoroptimaliseringsteknikker
Erfaring med tverrbaserte verktøykjeder

Once the test is sent to a candidate, the candidate receives a link in email to take the test. For each candidate, you will receive a detailed report with skills breakdown and benchmarks to shortlist the top candidates from your pool.

What topics are covered in the Innebygd C Online test?

C Grunnleggende:
Forstå variabler, datatyper, erklæringer og funksjoner i C er avgjørende for innebygd C -programmering da det danner grunnlaget for å skrive effektiv og optimalisert kode.
Embedded C Grunnleggende:
Mastering av registre, direktiver og drivere i innebygd C er avgjørende for å kontrollere og samhandle med maskinvarekomponenter som mikrokontrollere og perifere.
pekere: </h4> < P> pekere er en kraftig funksjon i C som muliggjør manipulering og tilgang til minneadresser. Kunnskap om pekere med matriser, strukturer og fagforeninger er viktig for minnestyring og effektiv databehandling. </p> <h4> Bitoperasjoner:
Bitoperasjoner involverer emballasje og pakking av data på bitnivå, som som I samsvar med å utføre forskjellige bitmanipulasjoner som innstilling, rydding eller slå på spesifikke biter. Denne ferdigheten er viktig i innebygde systemer der minne- og beregningsressurser er begrenset.
I/O i C og korrelasjoner i innebygde systemer:
Forstå inngangs-/utgangsoperasjoner i C og hvordan de Forhold til Embedded Systems er avgjørende for å utvikle sanntidsapplikasjoner og effektiv kommunikasjon mellom maskinvare- og programvarekomponenter.
Objektorienterte prinsipper:
Kunnskap om objektorienterte prinsipper som polymorfisme, arv , og innkapsling muliggjør utvikling av gjenbrukbar og modulær kode, forbedring av kodeorganisasjonen og vedlikeholdbarheten.
Internals av Assembler og Compiler:
Forstå internalen til samleren og kompilatoren gir innsikt i Samlingsprosessen og muliggjør optimalisering av kode for bedre ytelse og effektivitet.
Feilsøking og feilhåndtering:
Kompetanse i feilsøkingsteknikker og feilhåndtering er avgjørende for å feilsøke og identifisere og løse problemer i Innebygde C-programmer, som sikrer pålitelige og robuste applikasjoner.
kompilatoroptimalisering:
Å vite hvordan du optimaliserer kode ved å bruke kompilatorspesifikke funksjoner og alternativer muliggjør generering av raskere og mer effektive binærfiler, ledende For forbedret ytelse i innebygde systemer.
Tverrkomponeringsverktøykjeder:
Kunnskap om tverrkomponere verktøykjeder er avgjørende for å utvikle programvare på en plattform og generere kjørbare filer for en annen plattform, noe som er vanlig I det innebygde systemdomenet.
Headerbeskyttelse:
Forståelse av headerbeskyttelsesteknikker hjelper til med å forhindre problemer som flere inkludering og konflikter mellom overskriftsfiler, og sikrer renere og mer håndterbar kode i innebygde C -prosjekter.
oppstartssekvens:
Kjennskap til oppstartsekvensen til innebygde systemer er viktig for å forstå systemoppstartprosessen, initialisere maskinvarekomponenter og utføre hovedprogramkoden.
Full list of covered topics
The actual topics of the questions in the final test will depend on your job description and requirements. However, here's a list of topics you can expect the questions for Innebygd C -test to be based on.
Variabler
Datatyper
Erklæringer
Funksjoner
Registre
Direktiver
Drivere
Pekere
Matriser
Strukturer
Fagforeninger
Bitoperasjoner
Emballasjedata
Pakk ut data
Bitmanipulasjoner
I/O i C
Korrelasjoner i innebygde systemer
Objektorienterte prinsipper
Polymorfisme
Arv
Innkapsling
Assembler
Kompilator
Feilsøking
Feilhåndtering
Kompilatoroptimalisering
Tverrkomponering av verktøykjeder
Headerbeskyttelse
Oppstartssekvens

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What roles can I use the Innebygd C Online test for?

Embedded Software Engineer
Firmwareingeniør
Embedded Systems Developer
Mikrokontrolleringeniør
Embedded Systems Consultant
Elektroniske og elektriske ingeniører

How is the Innebygd C Online test customized for senior candidates?

For intermediate/ experienced candidates, we customize the assessment questions to include advanced topics and increase the difficulty level of the questions. This might include adding questions on topics like

Kompetanse innen overskriftsbeskyttelse i C
Forståelse av oppstartssekvensen i innebygde systemer
Kompetanse i håndtering av avbrytelser og tidtakere i innebygde systemer
Erfaring med å jobbe med forskjellige kommunikasjonsprotokoller (SPI, I2C, UART)
Forståelse av programvare-hardvareinteraksjoner i innebygde systemer
Kunnskap om sanntids operativsystemer (RTOs) og implementeringen av dem
Kjennskap til enhetsdrivere på lavt nivå og perifer programmering
Kompetanse i firmwareutvikling og feilsøking
Erfaring med optimaliseringsteknikker med lav effekt for innebygde systemer
Evne til å utføre testing og verifisering av systemnivå
Kompetanse i utforming og implementering av effektive algoritmer for innebygde systemer

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Ansettelseslederne mente at de gjennom de tekniske spørsmålene de stilte under panelintervjuene, var i stand til å fortelle hvilke kandidater som scoret bedre, og differensierte med de som ikke skåret like godt. De er svært fornøyd med kvaliteten på kandidatene som er på listen med Adaface-screeningen.

85%

Reduksjon i screeningstid

Se hele casestudien

Innebygd C Hiring Test Vanlige spørsmål

Kan jeg evaluere C-kodingsferdigheter og Embedded C-ferdigheter i samme test?

Ja. Du kan se vår standard C online test for å få en følelse av hva slags spørsmål som vil bli brukt til å evaluere C. Den siste testen vil ha MCQ-spørsmål for å evaluere C, Embedded C og kodespørsmål for å evaluere C-kodingsferdigheter.

Kan jeg evaluere C++ og Embedded C i samme test?

Ja. Du kan se vår standard C++ online test for å få en følelse av hva slags spørsmål som vil bli brukt til å evaluere C++. Den siste testen vil ha MCQ-spørsmål for å evaluere C++, Embedded C og kodespørsmål for å evaluere C/C++-kodingsferdighetene.

Kan jeg kombinere flere ferdigheter til en tilpasset vurdering?

Ja absolutt. Tilpassede vurderinger er satt opp basert på stillingsbeskrivelsen din, og vil inneholde spørsmål om alle må-ha ferdigheter du spesifiserer.

Har du noen anti-juksende eller proktoreringsfunksjoner på plass?

Vi har følgende anti-juksede funksjoner på plass:

Ikke-googlable spørsmål
IP Proctoring
Nettproctoring
Webcam Proctoring
Deteksjon av plagiering
Sikker nettleser

Les mer om Proctoring -funksjonene.

Hvordan tolker jeg testresultater?

Den viktigste tingen å huske på er at en vurdering er et eliminasjonsverktøy, ikke et seleksjonsverktøy. En ferdighetsvurdering er optimalisert for å hjelpe deg med å eliminere kandidater som ikke er teknisk kvalifisert for rollen, det er ikke optimalisert for å hjelpe deg med å finne den beste kandidaten for rollen. Så den ideelle måten å bruke en vurdering på er å bestemme en terskelpoeng (vanligvis 55%, vi hjelper deg med å benchmark) og invitere alle kandidater som scorer over terskelen for de neste rundene med intervjuet.

Hvilken opplevelsesnivå kan jeg bruke denne testen til?

Hver ADAFACE -vurdering er tilpasset din stillingsbeskrivelse/ ideell kandidatperson (våre fageksperter vil velge de riktige spørsmålene for din vurdering fra vårt bibliotek med 10000+ spørsmål). Denne vurderingen kan tilpasses for ethvert opplevelsesnivå.

Får hver kandidat de samme spørsmålene?

Ja, det gjør det mye lettere for deg å sammenligne kandidater. Alternativer for MCQ -spørsmål og rekkefølgen på spørsmål er randomisert. Vi har anti-juksing/proctoring funksjoner på plass. I vår bedriftsplan har vi også muligheten til å lage flere versjoner av den samme vurderingen med spørsmål med lignende vanskelighetsnivåer.